Math  /  Algebra

QuestionGiven 2x=162^{x}=16 and 2y=642^{y}=64, find: (a) 2x+y2^{x+y}, (b) 2xy2^{x-y}, (c) xyxy.

Studdy Solution
Calculate the value of xyx y.
xy=4×6=24x y =4 \times6 =24
So, the values of 2x+y2^{x+y}, 2xy2^{x-y}, and xyx y are1024,/4, and24 respectively.

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