Math  /  Data & Statistics

Question59. After once again losing a football game to the archrival, a college's alumni association conducted a survey to see if alumni were in favor of firing the coach. An SRS of 100 alumni from the population of all living alumni was taken, and 64 of the alumni in the sample were in favor of firing the coach. Suppose you wish to see if a majority of living alumni are in favor of firing the coach. The appropriate test statistic is (a) z=0.640.50.64(0.36)100z=\frac{0.64-0.5}{\sqrt{\frac{0.64(0.36)}{100}}} (d) z=0.640.50.64(0.36)64z=\frac{0.64-0.5}{\sqrt{\frac{0.64(0.36)}{64}}} (b) t=0.640.50.64(0.36)100t=\frac{0.64-0.5}{\sqrt{\frac{0.64(0.36)}{100}}} (e) z=0.50.640.5(0.5)100z=\frac{0.5-0.64}{\sqrt{\frac{0.5(0.5)}{100}}} (c) z=0.640.50.5(0.5)100z=\frac{0.64-0.5}{\sqrt{\frac{0.5(0.5)}{100}}}

Studdy Solution
Match the formula to the given options:
Using the formula:
z=0.640.50.5×0.5100 z = \frac{0.64 - 0.5}{\sqrt{\frac{0.5 \times 0.5}{100}}}
This matches option (c):
z=0.640.50.5(0.5)100 z = \frac{0.64 - 0.5}{\sqrt{\frac{0.5(0.5)}{100}}}
The appropriate test statistic is:
(c)z=0.640.50.5(0.5)100 \boxed{(c) \, z = \frac{0.64 - 0.5}{\sqrt{\frac{0.5(0.5)}{100}}}}

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