Question6. Solve for X 1) $\frac{x+1}{2}=\frac{3}{x}$ 2) $\frac{x-3}{7}=\frac{1}{x+3}$

Studdy Solution
Factor the quadratic equation:
$$(x - 4)(x + 4) = 0$$
Set each factor equal to zero and solve for $x$:
$$x - 4 = 0 \quad \text{or} \quad x + 4 = 0$$ $$x = 4 \quad \text{or} \quad x = -4$$
The solutions for $x$ are: 1) $x = -3$ or $x = 2$ for the first equation. 2) $x = 4$ or $x = -4$ for the second equation.