Math  /  Algebra

Question6.045. Арифметик прогрессийн 5 - р гишүүн нь 3 - р гишүүнээс 3 - аар их ба тэдгээрийн нийлбэр нь 10 бол 2p2-\mathrm{p} гишүүнийг ол. A. 2,4 B. 4 C. 8 D. 2 E. 8,4 6.046. Арифметик прогрессийн гурав ба зургаадугаар гишүүдийн нийлбэр 3,5 . Эхний 8 гишүүний нийлбэр ол. A. 1 B. 14 C. 12 D. 15 E. 2 6.047. Арифметик прогрессийн 6 - р гишүүн нь 4 - р гишүүнээсээ 8 - аар их ба тэдгээрийн нийлбэр 33 бол 3p3-\mathrm{p} гишүүнийг ол. A. 7,5 B. 9,5 C. 8,5 D. 5 E. 5,5

Studdy Solution
Find the 2p 2-\mathrm{p} term, which is the 2nd term: a2=a1+d a_2 = a_1 + d a2=12+32 a_2 = \frac{1}{2} + \frac{3}{2} a2=2 a_2 = 2
The answer is 2 \boxed{2} .
**Problem 6.046 Steps:**
STEP_1: Define the terms of the arithmetic progression. Let the first term be a1 a_1 and the common difference be d d .
STEP_2: The sum of the 3rd and 6th terms is 3.5: a3+a6=3.5 a_3 + a_6 = 3.5
STEP_3: Using the formula for the n n -th term: a3=a1+2d a_3 = a_1 + 2d a6=a1+5d a_6 = a_1 + 5d
Substitute these into the equation: a1+2d+a1+5d=3.5 a_1 + 2d + a_1 + 5d = 3.5 2a1+7d=3.5 2a_1 + 7d = 3.5
STEP_4: Solve for a1 a_1 and d d . Assume a1=x a_1 = x and d=y d = y : 2x+7y=3.5 2x + 7y = 3.5
Assume values or solve using additional information if available.
STEP_5: Calculate the sum of the first 8 terms: S8=82(2a1+7d) S_8 = \frac{8}{2} (2a_1 + 7d) S8=4×3.5 S_8 = 4 \times 3.5 S8=14 S_8 = 14
The answer is 14 \boxed{14} .
**Problem 6.047 Steps:**
STEP_1: Define the terms of the arithmetic progression. Let the first term be a1 a_1 and the common difference be d d .
STEP_2: The 6th term is 8 more than the 4th term: a6=a4+8 a_6 = a_4 + 8
The sum of the 6th and 4th terms is 33: a6+a4=33 a_6 + a_4 = 33
STEP_3: Using the formula for the n n -th term: a4=a1+3d a_4 = a_1 + 3d a6=a1+5d a_6 = a_1 + 5d
Substitute these into the equations: a1+5d=a1+3d+8 a_1 + 5d = a_1 + 3d + 8 a1+5d+a1+3d=33 a_1 + 5d + a_1 + 3d = 33
Simplify: 2d=8 2d = 8 2a1+8d=33 2a_1 + 8d = 33
STEP_4: Solve for d d : d=4 d = 4
Substitute d d into the second equation: 2a1+8×4=33 2a_1 + 8 \times 4 = 33 2a1+32=33 2a_1 + 32 = 33 2a1=1 2a_1 = 1 a1=12 a_1 = \frac{1}{2}
STEP_5: Find the 3p 3-\mathrm{p} term, which is the 3rd term: a3=a1+2d a_3 = a_1 + 2d a3=12+2×4 a_3 = \frac{1}{2} + 2 \times 4 a3=12+8 a_3 = \frac{1}{2} + 8 a3=8.5 a_3 = 8.5
The answer is 8.5 \boxed{8.5} .

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