Math  /  Data & Statistics

Question6.2.6. A random sample of size 16 is drawn from a normal distribution having σ=6.0\sigma=6.0 for the purpose of testing H0:μ=30H_{0}: \mu=30 versus H1:μ30H_{1}: \mu \neq 30. The experimenter chooses to define the critical region CC to be the set of sample means lying in the interval (29.9, 30.1). What level of significance does the test have? Why is (29.9,30.1)(29.9,30.1) a poor choice for the critical region? What range of yˉ\bar{y} values should comprise CC, assuming the same α\alpha is to be used?

Studdy Solution
Determine the appropriate critical region for the same α\alpha:
To find the appropriate critical region, we need to determine the z-scores that correspond to a total α\alpha of 0.0536 in the tails of the standard normal distribution. This requires finding the z-scores such that:
P(Z<z)+P(Z>z)=0.0536P(Z < -z) + P(Z > z) = 0.0536
This implies:
P(Z>z)=0.0268P(Z > z) = 0.0268
Using standard normal distribution tables or a calculator, find z1.96 z \approx 1.96 .
Thus, the appropriate critical region for the sample mean is:
yˉ=μ±zσyˉ=30±1.96×1.5\bar{y} = \mu \pm z \cdot \sigma_{\bar{y}} = 30 \pm 1.96 \times 1.5
C=(27.06,32.94)C = (27.06, 32.94)
The appropriate critical region for the same α\alpha is (27.06,32.94) (27.06, 32.94) .

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