Math  /  Trigonometry

Question[7(\cos 30^\circ + i \sin 30^\circ)][6(\cos 60^\circ + i \sin 60^\circ)] = \text{______}(\cos\text{______} + i \sin\text{______}) = \text{______} + \text{______}i [7(\cos 30^\circ + i \sin 30^\circ)][6(\cos 60^\circ + i \sin 60^\circ)] = \text{______}(\cos\text{______}^\circ + i \sin\text{______}^\circ) = \text{______} + \text{______}i

Studdy Solution
The product of the complex numbers in polar form is 42(cos90+isin90)42(\cos 90^\circ + i \sin 90^\circ).
In rectangular form, the result is 0+42i0 + 42i.

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