Math / CalculusQuestion7∫−2−1(6x2+2x−10)dx7 \quad \int_{-2}^{-1}\left(6 x^{2}+2 x-10\right) d x7∫−2−1(6x2+2x−10)dxStuddy SolutionMultiply the result by 7:7×1=7 7 \times 1 = 7 7×1=7 The value of the expression is:7 \boxed{7} 7View Full Solution - FreeWas this helpful?