Math  /  Data & Statistics

Question8. What proportion of a normal distribution is located between each of the following zz-score boundaries? a. z=0.25z=-0.25 and z=+0.25z=+0.25

Studdy Solution
Calculate the proportion of the distribution between z=0.25 z = -0.25 and z=+0.25 z = +0.25 by subtracting the cumulative probability at z=0.25 z = -0.25 from the cumulative probability at z=+0.25 z = +0.25 .
P(0.25<Z<+0.25)=P(Z<+0.25)P(Z<0.25) P(-0.25 < Z < +0.25) = P(Z < +0.25) - P(Z < -0.25)
P(0.25<Z<+0.25)=0.59870.4013=0.1974 P(-0.25 < Z < +0.25) = 0.5987 - 0.4013 = 0.1974
The proportion of the normal distribution located between z=0.25 z = -0.25 and z=+0.25 z = +0.25 is:
0.1974 \boxed{0.1974}

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