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Math  /  Geometry

Question9.03−9.069.03-9.06 Question 4 of 7 (1 point) I Question Attempt: 1 of Unlimited
In the figure below, m∠ABD=111∘,m∠CBD=64∘m \angle A B D=111^{\circ}, m \angle C B D=64^{\circ}, and BE‾\overline{B E} bisects ∠CBD\angle C B D. Find m∠ABEm \angle A B E. m∠ABE=□∘m \angle A B E=\square^{\circ}

Studdy Solution
Now, find ∠ABE\angle ABE by summing ∠ABD\angle ABD and ∠EBD\angle EBD.
∠ABE=∠ABD+∠EBD \angle ABE = \angle ABD + \angle EBD ∠ABE=111∘+34.5∘ \angle ABE = 111^\circ + 34.5^\circ ∠ABE=145.5∘ \angle ABE = 145.5^\circ
The solution is: m∠ABE=145.5∘ m \angle ABE = 145.5^\circ

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