QuestionFind the rotation rate in revolutions per second for a $32.5 \mathrm{ft}$ radius centrifuge to achieve $20.0 \mathrm{~g}$ acceleration.

Studdy Solution
Calculate the value of $\omega$$$\omega = \sqrt{\frac{643.48 \, \mathrm{ft/s^2}}{407.15 \, \mathrm{ft}}} =1.26 \, \mathrm{s^{-1}}$$The rotation rate required to give the astronaut a centripetal acceleration of $20.0 \, g$ is $1.26 \, \mathrm{s^{-1}}$ or $1.26$ revolutions per second.