Math  /  Algebra

QuestionA 5.0-gram ice cube at - 2.0 degrees Celsius is dropped into 60 grams of liquid water at 12 degrees Celsius. If the ice and water are isolated from the environment, what is the final temperature of the combined liquid water when all of the ice has melted and the mixture reaches thermal equilibrium? \square A \quad degrees Celsius \square Hide hint for Question 1 Report your result to 2 significant figures.

Studdy Solution
Solve for the final temperature Tf T_f .
1690.9=604.18(12Tf) 1690.9 = 60 \cdot 4.18 \cdot (12 - T_f)
1690.9=250.8(12Tf) 1690.9 = 250.8 \cdot (12 - T_f)
Divide both sides by 250.8: 12Tf=1690.9250.8 12 - T_f = \frac{1690.9}{250.8}
12Tf=6.74 12 - T_f = 6.74
Tf=126.74 T_f = 12 - 6.74
Tf=5.26 T_f = 5.26
Report the result to 2 significant figures: Tf=5.3°C T_f = 5.3 \, \text{°C}
The final temperature of the combined liquid water is:
5.3°C \boxed{5.3 \, \text{°C}}

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