QuestionA 56.0 cm long wrench is used to remove a lug nut from a car tire. If the torque needed to remove it is 107 Nm and you apply a force at the end of the wrench at an angle of $75.0^{\circ}$, how much force should you apply? 738 N 198 N 111 N 191 N
Question 3

Studdy Solution
Substitute the given values into the formula and calculate the force:
$$F = \frac{107 \text{ Nm}}{0.56 \text{ m} \cdot \sin(75.0^{\circ})}$$
Calculate $\sin(75.0^{\circ})$:
$$\sin(75.0^{\circ}) \approx 0.9659$$
Substitute this value:
$$F = \frac{107}{0.56 \times 0.9659}$$
$$F \approx \frac{107}{0.5409}$$
$$F \approx 197.8 \text{ N}$$
The closest answer choice is:
$$\boxed{198 \text{ N}}$$