QuestionA bag has 6 red, 10 green, 9 blue, and 11 yellow M&Ms. Find the probabilities of picking: 1) yellow, 2) blue or green, 3) orange.

Studdy Solution
The probability of picking an orange M&M is0, since there are no orange M&M's in the bag.
$$(Orange) =0$$So, the probability of picking a yellow M&M is $\frac{11}{36}$, the probability of picking a blue or green M&M is $\frac{19}{36}$, and the probability of picking an orange M&M is0.