Math  /  Calculus

QuestionA bottle of seltzer water initially has a temperature of 79F79^{\circ} \mathrm{F}. It is left to cool in a refrigerator that has a temperature of 40F40^{\circ} \mathrm{F}. After 10 minutes the temperature of the seltzer water is 66F66^{\circ} \mathrm{F}. Complete parts a through c . a. Use Newton's Law of Cooling, T=C+(T0C)ektT=C+\left(T_{0}-C\right) e^{k t}, to find a model for the temperature of the seltzer water, TT, after tt minutes. T=40+(39)e0.0405tT=40+(39) e^{-0.0405 t} (Simplify your answer. Use integers or decimals for any numbers in the equation. Round to four decimal places as needed) b. What is the temperature of the seltzer water after 15 minutes? 61F61^{\circ} \mathrm{F} (Round to nearest degree as needed.) c. When will the temperature of the seltzer water be 49F49^{\circ} \mathrm{F} ? \square minute(s) (Round to nearest minute as needed.)

Studdy Solution
Calculate t t : tln(0.2308)0.0405 t \approx \frac{\ln(0.2308)}{-0.0405} t1.4660.0405 t \approx \frac{-1.466}{-0.0405} t36.2 t \approx 36.2
Round to the nearest minute: t36 minutes t \approx 36 \text{ minutes}
The temperature of the seltzer water will be 49F 49^{\circ} \mathrm{F} after approximately 36 36 minutes.

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