Math  /  Calculus

QuestionA conical tank (vertex down) is 7 meters across the top and 9 meters deep. If the depth of the water (the height) is decreasing at 6.6 meters per minute, what is the change in the volume of the water in the tank when the height of the water in the tank is 4 meters?
Include units on your final answer, and your answer must be entered as number (not 5*7+3).

Studdy Solution
Simplify the expression: dVdt=3874.8π243 \frac{dV}{dt} = -\frac{3874.8 \pi}{243} dVdt50.2π \frac{dV}{dt} \approx -50.2 \pi
The change in the volume of the water in the tank when the height is 4 meters is approximately: 157.7 cubic meters per minute \boxed{-157.7} \text{ cubic meters per minute}

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