Math  /  Data & Statistics

QuestionA data set includes 103 body temperatures of healthy adult humans having a mean of 98.3F98.3^{\circ} \mathrm{F} and a standard deviation of 0.73F0.73^{\circ} \mathrm{F}. Construct a 99%99 \% confidence interval estimate of the mean body temperature of all healthy humans. What does the sample suggest about the use of 98.6F98.6^{\circ} \mathrm{F} as the mean body temperature? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table.
What is the confidence interval estimate of the population mean μ\mu ? \square \square F<μ<F{ }^{\circ} \mathrm{F}<\mu<\square^{\circ} \mathrm{F} (Round to three decimal places as needed.)

Studdy Solution
Interpret the confidence interval: The interval 98.111F<μ<98.489F 98.111^{\circ} \mathrm{F} < \mu < 98.489^{\circ} \mathrm{F} suggests that the mean body temperature of all healthy humans is likely lower than the commonly used value of 98.6F 98.6^{\circ} \mathrm{F} .
The confidence interval estimate of the population mean μ\mu is:
98.111F<μ<98.489F98.111^{\circ} \mathrm{F} < \mu < 98.489^{\circ} \mathrm{F}

View Full Solution - Free
Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord