QuestionA data set includes 105 body temperatures of healthy adult humans having a mean of $98.7^{\circ} \mathrm{F}$ and a standard deviation of $0.64^{\circ} \mathrm{F}$. Construct a $99 \%$ confidence interval estimate of the mean body temperature of all healthy humans. What does the sample suggest about the use of $98.6^{\circ} \mathrm{F}$ as the mean body temperature?
Click here to view a $t$ distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table.
What is the confidence interval estimate of the population mean $\mu$ ? $\square$ $\square$ ${ }^{\circ} \mathrm{F}<\mu<\square^{\circ} \mathrm{F}$ (Round to three decimal places as needed.) $t$ Distribution: Critical $t$ Values \begin{tabular}{|c|cc|} \hline & 0.005 & 0.01 \\ \hline \begin{tabular}{c} Degrees of \\ Freedom \end{tabular} & 0.01 & 0.02 \\ \hline 1 & 63.657 & 31.821 \\ \hline 2 & 9.925 & 6.965 \\ 3 & 5.841 & 4.541 \\ \hline 4 & 4.604 & 3.747 \\ 5 & 4.032 & 3.365 \\ 6 & 3.707 & 3.143 \\ 7 & 3.499 & 2.998 \\ 8 & 3.355 & 2.896 \\ 9 & 3.250 & 2.821 \\ \hline \end{tabular}