Math  /  Data & Statistics

QuestionA data set includes data from student evaluations of courses. The summary statistics are n=92,xˉ=3.42,s=0.58n=92, \bar{x}=3.42, s=0.58. Use a 0.05 significance level to test the claim that the population of student course evaluations has a mean equal to 3.50 . Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
What are the null and alternative hypotheses? A. H0:μ=3.50H_{0}: \mu=3.50 B. H0:μ=3.50H_{0}: \mu=3.50 H1:μ<3.50H_{1}: \mu<3.50 H1:μ>3.50\mathrm{H}_{1}: \mu>3.50 C. H0:μ3.50\mathrm{H}_{0}: \mu \neq 3.50 D. H0:μ=3.50H_{0}: \mu=3.50 H1:μ=3.50H_{1}: \mu=3.50 H0:μ=3.50H1:μ3.50\begin{array}{l} H_{0}: \mu=3.50 \\ H_{1}: \mu \neq 3.50 \end{array}

Studdy Solution
State the conclusion based on the P-value and significance level.
Since the P-value 0.189 0.189 is greater than the significance level α=0.05 \alpha = 0.05 , we fail to reject the null hypothesis.
Conclusion: There is not enough evidence to support the claim that the population mean is different from 3.50.

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