Math  /  Geometry

Question(a) Find ADAD given tan50=AD12\tan 50^{\circ} = \frac{AD}{12}, where AD=14.30AD = 14.30. (b) Calculate angle BACBAC and verify it rounds to 40.4240.42^{\circ}. (c) Determine the area of quadrilateral ABCDABCD. (d) Find the shortest distance from BB to line ACAC.

Studdy Solution
Calculate the shortest distance from B to AC.
BD=2×cm2cm=cmBD_{\perp} = \frac{2 \times \ldots \, cm^2}{\ldots \, cm} = \ldots \, cmThe area of the quadrilateral ABC is cm2\ldots \, cm^2 and the shortest distance from B to AC is cm\ldots \, cm.

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