Question4 Formula 2 points A force of magnitude 40 is applied to an object at angle 17 above horizontal as shown below. What is the $x$-component of force Fin newtons? Enter only a numb in the blank. Round your answer to the nearest tenth (i.e. one decimal place).
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Studdy Solution
Calculate the $x$-component of the force. First, find $\cos(17^\circ)$ using a calculator:
$$\cos(17^\circ) \approx 0.9563$$
Now, calculate the product:
$$F_x = 40 \cdot 0.9563 \approx 38.252$$
Round the result to the nearest tenth:
$$F_x \approx 38.3$$
The $x$-component of the force is:
$$\boxed{38.3}$$