Math  /  Algebra

QuestionA graphing calculator will be available for this question. If log2bx5=Tand b>12\log _{2 b} x^{5}=T_{\text {and }} b>\frac{1}{2}, then x=x= (2b)5T(2 b)^{5 T} 2b5T2 b^{5 T} (2b)T5\frac{(2 b)^{T}}{5} (2b)T5(2 b)^{\frac{T}{5}} 2bT52 b^{\frac{T}{5}}

Studdy Solution
Verify which option matches the derived expression for xx:
The expression x=(2b)T5x = (2b)^{\frac{T}{5}} matches the option:
(2b)T5(2b)^{\frac{T}{5}}
The value of xx is:
(2b)T5(2b)^{\frac{T}{5}}

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