Math  /  Algebra

Question1 ■ Mark for Review
A hawk with mass 1 kg dives straight downward. At time t1t_{1}, the hawk has a speed of 20 m/s20 \mathrm{~m} / \mathrm{s}. At time t2t_{2}, the hawk has a speed of 50 m/s50 \mathrm{~m} / \mathrm{s}. The change in the kinetic energy of the hawk between t1t_{1} and t2t_{2} is most nearly (A) 200 J (B) 450 J (C) 1050 J (D) 1250 J

Studdy Solution
Determine the change in kinetic energy by subtracting the initial kinetic energy from the final kinetic energy:
ΔKE=KE2KE1 \Delta KE = KE_2 - KE_1
ΔKE=1250J200J \Delta KE = 1250 \, \mathrm{J} - 200 \, \mathrm{J}
ΔKE=1050J \Delta KE = 1050 \, \mathrm{J}
The change in kinetic energy of the hawk between t1 t_1 and t2 t_2 is most nearly:
1050J \boxed{1050 \, \mathrm{J}}

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