QuestionFind the horizontal distance a jet climbs with slope $m=3/8$ to reach $12,000$ ft altitude.

Studdy Solution
olve the division to find the horizontal distance.
$$run =12,000 \times \frac{8}{3} =32,000 \, ft$$The airplane will fly $32,000$ ft in the horizontal direction to reach an altitude of $12,000$ ft above the takeoff point.