Math  /  Algebra

Question(a) log411+log47=log4\log _{4} 11+\log _{4} 7=\log _{4}

Studdy Solution
Simplify the expression inside the logarithm:
117=7711 \cdot 7 = 77
Thus, the expression becomes:
log477\log_4 77
The expression log411+log47\log_4 11 + \log_4 7 simplifies to log477\log_4 77.

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