QuestionA steel rod of length $L_{0}$ at $T_{0}$ changes length with $\Delta L=\alpha L_{0} \Delta T$. Find lengths for given temps.

Studdy Solution
Plug in the values for $_{0}$ and $_{0}$ to get the function.
$$=50 +.24 \times10^{-} \times50 \times ( -130)$$The length of the rod at different temperatures can be calculated by substituting the value of $$ in the above equation.