QuestionA particle is moving with the given data. Find the position of the part (b) $a(t)=2 t+1 s(0)=3, v(0)=-L$

Studdy Solution
Substitute $C_2$ back into the position function:
$$s(t) = \frac{t^3}{3} + \frac{t^2}{2} - 2t + 3$$
The position function of the particle is:
$$s(t) = \frac{t^3}{3} + \frac{t^2}{2} - 2t + 3$$