QuestionA particle's velocity is $v(t)=e^{t-1}-3 \sin (t-1)$. What is its motion at $t=1$? (a) speeding up, (b) slowing down, (c) neither, (d) at rest.

Studdy Solution
This means that the acceleration of the particle at $t=$ is negative, which tells us the particle is slowing down because the velocity and acceleration have opposite signs.The solution to the problem is "The particle is slowing down at $t=$".