QuestionA photon with wavelength $1.57 \mathrm{~nm}$ emits an electron with $61.5 \mathrm{eV}$. Find the binding energy in J.

Studdy Solution
Calculate the binding energy of the electron.
$$_{binding} =.266 \times^{-18} \, J -9.854 \times^{-18} \, J =3.12 \times^{-19} \, J$$The binding energy of the electron is $3.12 \times^{-19} \, J$.