Math  /  Trigonometry

Question\begin{problem} A plane flying at an altitude of 4 miles travels on a path directly over a radar tower.
(a) Express the distance d(t)d(t) (in miles) between the plane and the tower as a function of the angle tt in standard position from the tower to the plane.
d(t)=cscsin[ d(t) = \square \csc \square \square \sin [ \end{problem}

Studdy Solution
Recognize that 1sin(t)\frac{1}{\sin(t)} is the definition of the cosecant function, csc(t)\csc(t): d(t)=4csc(t)d(t) = 4 \csc(t)
The expression for the distance d(t) d(t) as a function of the angle t t is:
d(t)=4csc(t) d(t) = 4 \csc(t)

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