Math  /  Measurement

Question Find the lengths of the legs of a right triangle where the first leg is 1 cm longer than the second, and the hypotenuse is 6 cm.
First Leg: 36x2+1 cm\text{First Leg: } \sqrt{36 - x^2} + 1 \text{ cm} Second Leg: 36x2 cm\text{Second Leg: } \sqrt{36 - x^2} \text{ cm}

Studdy Solution
Now we have the exact lengths of both legs:
First Leg: 1+712 cm\frac{1 + \sqrt{71}}{2} \mathrm{~cm}
Second Leg: 1+712 cm\frac{-1 + \sqrt{71}}{2} \mathrm{~cm}

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