QuestionA training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is $89$ m long and $62$ m wide. Find the area of the training field. Use the value $3.14$ for $\pi$, and do not round your answer. Be sure to include the correct unit in your answer.

Studdy Solution
Sum the areas of the rectangle and the semicircles to find the total area:
$$\text{Total Area} = \text{Area}_{\text{rectangle}} + \text{Area}_{\text{semicircles}}$$
$$= 5518 \, \text{m}^2 + 3016.54 \, \text{m}^2$$
$$= 8534.54 \, \text{m}^2$$
The area of the training field is:
$$\boxed{8534.54 \, \text{m}^2}$$