Math  /  Geometry

QuestionA training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 83 m long and 58 m wide. What is the length of a training track running around the field?
Do not round any intermediate computations. Round your final answer to the nearest hundredth and be sure to include the correct unit. If necessary, refer to the list of geometry formulas. \square m m2m^{2} m3\mathrm{m}^{3}

Studdy Solution
Calculate the total length:
Total length of track=166+π×58 \text{Total length of track} = 166 + \pi \times 58
Using π3.14159 \pi \approx 3.14159 :
Total length of track=166+3.14159×58 \text{Total length of track} = 166 + 3.14159 \times 58
Total length of track=166+182.21222 \text{Total length of track} = 166 + 182.21222
Total length of track=348.21222 \text{Total length of track} = 348.21222
Round to the nearest hundredth:
Total length of track348.21m \text{Total length of track} \approx 348.21 \, \text{m}
The length of the training track running around the field is:
348.21m \boxed{348.21 \, \text{m}}

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