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Math  /  Word Problems

QuestionA water sample absorbed 2,851 J2,851 \mathrm{~J} from a 42.6 g42.6 \mathrm{~g} metal piece cooling from 209∘C209^{\circ} \mathrm{C} to 40.0∘C40.0^{\circ} \mathrm{C}. Find the specific heat of the metal: Cmetal =[?]Jg⋅∘C\mathrm{C}_{\text {metal }}=[?] \frac{\mathrm{J}}{\mathrm{g} \cdot{ }^{\circ} \mathrm{C}}.

Studdy Solution
Take the absolute value of CCC=∣−.399Jg⋅°C∣=.399Jg⋅°CC = |-.399 \frac{J}{g \cdot °C}| =.399 \frac{J}{g \cdot °C}The specific heat capacity of the metal is .399Jg⋅°C.399 \frac{J}{g \cdot °C}.

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