Math / Calculus

QuestionA weight on a vertical spring is given an initial upward velocity of $5 \mathrm{~cm} / \mathrm{sec}$ from a point 7 cm below equilibrium. Assume that the contstant $\omega$ has a value of 0.1 . Write the formula for the location of the weight at time $t$ . $x=$
Find the location of the weight 5 seconds after it is set in motion. centimeters

Studdy Solution
The formula for the location of the weight at time $t$ is $x(t) = 50.49 \cos(0.1t + 1.44)$ .
After 5 seconds, the weight is approximately -16.66 cm from equilibrium (i.e., about 16.66 cm below equilibrium).

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