Math  /  Algebra

QuestionFind pp in x3x2=xpx^{3} \cdot x^{2}=x^{p} and rr in (x3)2=xr\left(x^{3}\right)^{2}=x^{r}.

Studdy Solution
By comparing the two sides of the equation, we can see that the exponents must be equal for the equation to hold true. Therefore, r=6r=6.
So, the solution to the problem is p=5p=5 and r=6r=6.

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