Question(A) $x=14$ and $y=14$ (C) $x=14$ and $y=14 \sqrt{2}$
B $y=7$ and $x=7 \sqrt{3}$ Zoom then $45^{\circ}$ 14 $y$ $\square$ $\qquad$

Studdy Solution
We found that $x = 7\sqrt{2}$ and $y = 7\sqrt{2}$.
None of the given options match exactly, but if we multiply $7\sqrt{2}$ by $\sqrt{2}$ we get $7 \cdot 2 = 14$.
So, it looks like there's a typo in the problem, and the correct answer should be $x = 7\sqrt{2}$ and $y = 7\sqrt{2}$.
If we assume the problem meant to have $x=14/\sqrt{2}$ and $y=14/\sqrt{2}$, then after rationalizing the denominator, we get $x=7\sqrt{2}$ and $y=7\sqrt{2}$.