Question$AB = 6$ cm $AD = 8$ cm $m\angle{C} = 45^\circ$ $BM \perp CD$ $BM = \boxed{\phantom{00}}$ cm $DM = \boxed{\phantom{00}}$ cm $MC = \boxed{\phantom{00}}$ cm $DC = \boxed{\phantom{00}}$ cm Fie trapezul dreptunghic de mai sus în care $BM \perp CD$. Folosind datele din figură obținem:

Studdy Solution
Given that $BM = MC$ and using the properties of the 45-45-90 triangle, we find:
- $BM = 6 \, \text{cm}$ - $DM = 8 \, \text{cm} - 6 \, \text{cm} = 2 \, \text{cm}$ - $MC = 6 \, \text{cm}$ - $DC = 6 \, \text{cm} \cdot \sqrt{2} \approx 8.49 \, \text{cm}$