QuestionAdd the fractions $\frac{8}{x-2}$ and $\frac{2}{x-3}$.

Studdy Solution
implify the numerator by combining like terms.
$$\frac{8x-24+2x-4}{(x-2)(x-3)} = \frac{10x-28}{(x-2)(x-3)}$$So, the sum of the fractions $\frac{8}{x-2}$ and $\frac{2}{x-3}$ is $\frac{10x-28}{(x-2)(x-3)}$.