Math  /  Calculus

QuestionAll changes saved
The power, PP, dissipated when a 11 -volt battery is put across a resistance of RR ohms is given by P=121RP=\frac{121}{R}
What is the rate of change of power with respect to resistance? rate of change ==

Studdy Solution
Simplify the expression for the rate of change.
dPdR=121R2 \frac{dP}{dR} = -\frac{121}{R^2}
The rate of change of power with respect to resistance is:
121R2 \boxed{-\frac{121}{R^2}}

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