QuestionAn 80.0 kg man stands on a scale inside an elevator. What is the weight in Newtons that the scale reads when the elevator is: a. At rest b. Moving upward at a constant speed of $5.00 \mathrm{~m} / \mathrm{s}$ c. Moving downward at a constant speed of $5.00 \mathrm{~m} / \mathrm{s}$ d. Moving with an upward acceleration of $3.00 \mathrm{~m} / \mathrm{s} / \mathrm{s}$ e. Moving with a downward acceleration of $4.00 \mathrm{~m} / \mathrm{s} / \mathrm{s}$

Studdy Solution
When accelerating downward, the net force is the gravitational force minus the force due to acceleration.
Net force when accelerating downward: $$F_{\text{net}} = m(g - a) = 80.0 \, \text{kg} \times (9.81 \, \text{m/s}^2 - 4.00 \, \text{m/s}^2) = 464.8 \, \text{N}$$
The weights read by the scale are: a. At rest: $784.8 \, \text{N}$ b. Moving upward at constant speed: $784.8 \, \text{N}$ c. Moving downward at constant speed: $784.8 \, \text{N}$ d. Moving with upward acceleration: $1024.8 \, \text{N}$ e. Moving with downward acceleration: $464.8 \, \text{N}$