QuestionAn applied force of 856 N [Right] acts on a 241 kg mass, causing it to accelerate at $1.34 \mathrm{~m} / \mathrm{s}^{2}$ [Right]. Wind resistance of 127 N [Left] acts on the mass and an unknown frictional force, $\mathrm{F}_{\mathrm{f}}$, also acts to the Left. Determine the unknown force of friction, $\mathrm{F}_{\mathrm{f}}$. (3 marks)

Studdy Solution
The net force is also the sum of all forces acting on the mass:
$$F_{\text{net}} = F_{\text{applied}} - F_{\text{wind}} - F_{\text{f}}$$
Substitute the known values:
$$323.74 \, \text{N} = 856 \, \text{N} - 127 \, \text{N} - F_{\text{f}}$$
Simplify the equation:
$$323.74 \, \text{N} = 729 \, \text{N} - F_{\text{f}}$$
Solve for $F_{\text{f}}$:
$$F_{\text{f}} = 729 \, \text{N} - 323.74 \, \text{N} = 405.26 \, \text{N}$$
The unknown force of friction is:
$$\boxed{405.26 \, \text{N}}$$