Math  /  Algebra

QuestionAn object is thrown upward at a speed of 193 feet per second by a machine from a height of 3 feet off the ground. The height hh of the object after tt seconds can be found using the equation h=16t2+193t+3h=-16 t^{2}+193 t+3
When will the height be 150 feet? \square Select an answer \vee
When will the object reach the ground? \square Select an answer \checkmark

Studdy Solution
Interpret the solutions. The object reaches the ground at t=0 t = 0 (initially) and t=12.0625 t = 12.0625 seconds.
The object will reach the ground at t=12.0625 t = 12.0625 seconds after being thrown.

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