QuestionArrange $2^{16}, 4^{7}, 8^{5}$, and $64^{3}$ in ascending order with "$<$".

Studdy Solution
Substituting the original expressions for each $^{x}$, we get the final arrangement$$4^{7} <8^{5} <^{16} <64^{3}$$So, the numbers $^{16}$, $4^{7}$, $8^{5}$, and $64^{3}$ arranged in ascending order are $4^{7}$, $8^{5}$, $^{16}$, and $64^{3}$.