Math  /  Data & Statistics

QuestionAssume that a sample is used to estimate a population mean μ\mu. Find the 80%80 \% confidence interval for a sample of size 41 with a mean of 38.5 and a standard deviation of 18.5. Enter your answer as an openinterval (i.e., parentheses) accurate to 3 decimal places.
80\% C.I. = \square The answer should be obtained without any preliminary rounding.

Studdy Solution
Determine the confidence interval:
Lower limit=xˉME=38.53.764=34.736\text{Lower limit} = \bar{x} - \text{ME} = 38.5 - 3.764 = 34.736
Upper limit=xˉ+ME=38.5+3.764=42.264\text{Upper limit} = \bar{x} + \text{ME} = 38.5 + 3.764 = 42.264
The 80% confidence interval is:
(34.736,42.264)(34.736, 42.264)
80% C.I. = (34.736,42.264)(34.736, 42.264)

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