QuestionAssume $X$ has a normal distribution $N\left(9,5^{2}\right)$. Find $E(5 X-4)^{2}$
Answer: $\square$

Studdy Solution
Now, substitute these values into the formula for $E(Y^2)$:
$$E(Y^2) = \text{Var}(Y) + [E(Y)]^2 = 625 + 41^2$$
Calculate $41^2$:
$$41^2 = 1681$$
Therefore:
$$E(Y^2) = 625 + 1681 = 2306$$
The expected value $E(5X - 4)^2$ is $\boxed{2306}$.