Math  /  Geometry

QuestionFind mABDm \angle A B D, mCBDm \angle C B D, and mABCm \angle A B C given that BDundefined\overrightarrow{B D} bisects ABC\angle A B C and mABC=(25x+34)m \angle A B C=(25 x+34)^{\circ}.

Studdy Solution
The measure of ABC\angle A B C is given by (25x+34)(25 x+34)^{\circ}.
So, the measures of the angles aremABD=(25x+34)2m \angle A B D = \frac{(25 x+34)^{\circ}}{2}mCBD=(25x+34)2m \angle C B D = \frac{(25 x+34)^{\circ}}{2}mABC=(25x+34)m \angle A B C = (25 x+34)^{\circ}

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