QuestionBefore toothpaste was invented, people sometimes used calcium carbonate, $\mathrm{CaCO}_{3}(\mathrm{~s})$ , to clean their teeth. What mass of calcium carbonate can be precipitated by reacting 80.0 mL of a $0.100 \mathrm{~mol} / \mathrm{L}$ solution of sodium carbonate, $\mathrm{Na}_{2} \mathrm{CO}_{3}(\mathrm{aq})$ , with 50.0 mL of a $0.100 \mathrm{~mol} / \mathrm{L}$ solution of calcium chloride, $\mathrm{CaCl}_{2}(\mathrm{aq})$ ?

Studdy Solution
Convert moles of calcium carbonate to mass.
The molar mass of $\text{CaCO}_3$ is approximately 100.09 g/mol.
$\text{Mass of CaCO}_3 = \text{Moles} \times \text{Molar mass}$ $= 0.005 \, \text{mol} \times 100.09 \, \text{g/mol}$ $= 0.50045 \, \text{g}$
The mass of calcium carbonate precipitated is:
$\boxed{0.500 \, \text{g}}$

View Full Solution - Free

Was this helpful?

Get Studdy

Scan QR code with your device to get Studdy on iOS or Android

QR code

Studdy solves anything!

Download the app

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

Parents Influencer program Contact Policy Terms