QuestionБодлого, дасгал
1. a) $\sqrt{3}$ б) $\sqrt{5}$
2. a) $1+\sqrt{2}$ в) $\sqrt{7}$ тоонууд иррационал тоо гэж батал.

Studdy Solution
Conclude that both $a$ and $b$ must be divisible by 7, leading to a contradiction.
All numbers $\sqrt{3}$, $\sqrt{5}$, $1+\sqrt{2}$, and $\sqrt{7}$ are irrational.