Math  /  Algebra

QuestionBramplo 1 Use substitution to solve the system of equations. y=2x4xy=4\begin{array}{l} y=2 x \\ 4 x-y=-4 \end{array}
Substitute 2x2 x for yy in the second equation. 4xy=4 Second equation 4x2x=4y2x2x=4 Corbine like terms. x=2 Divide each side by 2 and smpify. \begin{array}{rl} 4 x-y=-4 & \text { Second equation } \\ 4 x-2 x=-4 & y-2 x \\ 2 x=-4 & \text { Corbine like terms. } \\ x=-2 & \text { Divide each side by } 2 \\ & \text { and smpify. } \end{array}
Use y=2xy=2 x to find the value of yy. y=2x First equation y=2(2)x=2y=4 Simplity. \begin{array}{ll} y=2 x & \text { First equation } \\ y=2(-2) & x=-2 \\ y=-4 & \text { Simplity. } \end{array}
The solution is (2,4)(-2,-4).
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Studdy Solution
The solution is (-2,-4)(\textbf{-2}, \textbf{-4}), meaning x=-2x = \textbf{-2} and y=-4y = \textbf{-4}.

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