Questionbreath, which is the limiting reactant? (4 $180.18 \mathrm{~g} / \mathrm{mol} 32^{2} \cdot \mathrm{ciog} / \mathrm{mal} \sim \infty 60_{2}(0.008125 \mathrm{mul})$ is the $$\frac{2.94 \mathrm{~g}}{180.18 \mathrm{~g} \mathrm{hol}}=0.0163 \mathrm{~mol} \quad \frac{0.26 \mathrm{~g}}{32.00 \mathrm{~g} / \mathrm{mol}}=0.008125 \mathrm{~mol}$$ (d) How much carbon dioxide will be produced in grams? (3 marks)